Use a wrapper around xml.etree.ElementTree.fromstring in python 2.x (#7178)

[youtube-dl] / youtube_dl / utils.py

diff --git a/youtube_dl/utils.py b/youtube_dl/utils.py
index db5b3698e748074e33752bc22266b45375a3b7c2..7d846d68085cdbf13e88f116b30b0ad9f2f21b0c 100644 (file)
--- a/youtube_dl/utils.py
+++ b/youtube_dl/utils.py
@@ -36,6 +36,7 @@ import zlib
 from .compat import (
     compat_basestring,
     compat_chr,
+    compat_etree_fromstring,
     compat_html_entities,
     compat_http_client,
     compat_kwargs,
@@ -1701,8 +1702,8 @@ def js_to_json(code):
         if v in ('true', 'false', 'null'):
             return v
         if v.startswith('"'):
-            return v
-        if v.startswith("'"):
+            v = re.sub(r"\\'", "'", v[1:-1])
+        elif v.startswith("'"):
             v = v[1:-1]
             v = re.sub(r"\\\\|\\'|\"", lambda m: {
                 '\\\\': '\\\\',
@@ -1974,7 +1975,7 @@ def dfxp2srt(dfxp_data):
 
         return out
 
-    dfxp = xml.etree.ElementTree.fromstring(dfxp_data.encode('utf-8'))
+    dfxp = compat_etree_fromstring(dfxp_data.encode('utf-8'))
     out = []
     paras = dfxp.findall(_x('.//ttml:p')) or dfxp.findall(_x('.//ttaf1:p')) or dfxp.findall('.//p')